2012A3a A thin uniform wire is bent to form the two equal sides AB and AC of triangle ABC, whereAB = AC = 5 cm. The third side BC, of length 6cm, is made from uniform wire of twice the linear massdensity of the first. The distance of centre of mass from A is(C) cm3434(A) cm(B) 4 cm(D) cm45uniform rectangular plate as shown in figure. The

2012A3a A thin uniform wire is bent to form the two equal sides AB and

1.	2012A3a A thin uniform wire is bent to form the two equal sides AB and AC of triangle ABC, whereAB = AC = 5 cm. The third side BC, of length 6cm, is made from uniform wire of twice the linear massdensity of the first. The distance of centre of mass from A is(C) cm3434(A) cm(B) 4 cm(D) cm45uniform rectangular plate as shown in figure. The
Answer» <p>weight is concentraed at centre of each rod</p><p>let mass of AB=AC=d.5.A ,its C.O.M are (4.5 , 2) and (1.5 , 2)</p><p>let mass of BC=2d.6.A ,its C.O.M are (3 , 0)</p><p>COMx = (54.5 +51.5+312)/(5+5+12) = 3</p><p>COMy = (52 +52+012)/(5+5+12) = 0.91</p><p>distance P(3 , 0.91) and A(3 , 4) is3.09m</p><p>ie 34/11cm</p>