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20Omega resistor is connected with the A.C. source of V = 282sin (120 pit), the current passing through the resistor will be …….. |
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Answer» 14.1 A with the equation `V=V_m sin omegat` `V_m`=282 V, `OMEGA=120 PI` rad/s , R=20 `Omega` `THEREFORE I_(rms)=I_m/sqrt2` `=V_m/(sqrt2R)=282/(1.41xx20)`=10 A |
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