1.

20Omega resistor is connected with the A.C. source of V = 282sin (120 pit), the current passing through the resistor will be ……..

Answer»

14.1 A
10A
7.05 A
5A

Solution :Comparing EQUATION `V=282 SIN (120pit)`
with the equation `V=V_m sin omegat`
`V_m`=282 V, `OMEGA=120 PI` rad/s , R=20 `Omega`
`THEREFORE I_(rms)=I_m/sqrt2`
`=V_m/(sqrt2R)=282/(1.41xx20)`=10 A


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