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21. A particle moves in an x-y plane with only ax-component of acceleration of 2 m/s. The particlestarts from the origin at t = 0 wihaving an x-component of 8 m/s and y-component ofth an initial ve15 m/s. The total velocity vector, at any time 't', is(I) [(8 +20i - 15j] m/s(2) (8i 15 j] m/s(3) [2t i + 15 j] m/s(4) [2ti - 15 j] m/s |
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Answer» For x – direction first, Applying the eqns. of motion, v1 = u1 + at v1 = 8i + 2i*t => (8 + 2t)i ….........................(1) For y – direction. acceleration is zero. thus velocity remains constant. v2 = u2 v2 = -15j …................(2) Thus resultant velocity of particle at time t from eqnns. (1) and (2) is given by: v = v1 + v2 v =(8 + 2t)i – 15j m/s. |
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