1.

211.Calculate the rms speed of ozone kept in a closed vessel at 20°C and 82 cm Hg pressure.

Answer»

C√3PV/M,P1V1/T1=P2V2/T2

Where,P1= 82 cm = 82 * 13.61 * 981 dynes

V1= Volume of gas at 82 cm and 20oC

P2,V2andT2are the conditions at NTP,

=>V1=P2V2/T2*T1/P1= 76.0 *22400/273 * 293/82 = 22282 cc

M = molecular weight of ozone (O3) = 48

∴ C = √3 *(82 * 13.6 * 981.) * 22282/48

= 3.9 *104cm sec^-1



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