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211.Calculate the rms speed of ozone kept in a closed vessel at 20°C and 82 cm Hg pressure.

Answer» <p>C√3PV/M,P1V1/T1=P2V2/T2</p><p>Where,P1= 82 cm = 82 * 13.61 * 981 dynes</p><p>V1= Volume of gas at 82 cm and 20oC</p><p>P2,V2andT2are the conditions at NTP,</p><p>=&gt;V1=P2V2/T2*T1/P1= 76.0 *22400/273 * 293/82 = 22282 cc</p><p>M = molecular weight of ozone (O3) = 48</p><p>∴ C = √3 *(82 * 13.6 * 981.) * 22282/48</p><p>= 3.9 *104cm sec^-1</p>


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