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22. An ideal solution was obtained by mixing methanol andethanol. If the partial vapour pressure of methanol andethanol are 2.619 K Pa and 4.556 K Pa respectivelythe composition of vapour (in terms of mole fraction)will be(1) 0.635 MeOH, 0.365 EtOH(2) 0.365 MeOH, 0.635 EtOH(3) 0.574 MeOH, 0.326 EtOH(4) 0.173 MeOH, 0.827 EtOH

Answer»

2 : 0.365Methanol 0.635Ethanol.

Steps:1) Find Total vapour pressure of solution by adding partial vapour pressures. P(T) = 2.619+4.556= 7.175

2)We know that,

X(Methanol) = Partial Pressure (Methanol) / P(T)= 2.619/7.175 = 0.365

3) Similarly, X(Ethanol) = 4.556/7.175 = 0.634

Therefore, composition of Methanol and Ethanol (Mole fraction) is 0.365 and 0.634 respectively.



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