InterviewSolution
Saved Bookmarks
| 1. |
227.Theuncertaintyinmomentumofanelectronis1x10-3kg-m/s.The uncertainty in its position will be(h 6.62 x 10-34 kg -m2/s)(a) 1.05 x10-25 m(b) 1.05x 10-2620 m (c) 5.27x10-30 m(d) 5 25x 1028 m |
|
Answer» we know that ∆x.∆p≥h/4π →1×10^-5×∆x≥6.6×10^-34/4×3.14 →∆x≥6.6×10^-34/(4×3.14)(10^-5) →∆x≥0.525×10^-29 →∆x≥5.25×10^-30m the minimum value is 5.25×10^-30m it's 5.27*10^-30m |
|