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23. The total energy of the electron ir the hydrogen atom inthe ground state is -13.6 eV. The KE of this electron is:pal13.6 eV(c)-13.6 eV(b) ze o(d) 6.8 eV

Answer»

Total E=-2*kehence ke=E/-2hence ke=-13.6/-2=6.8eV

answer is 13.6



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