23×(−99)=a×(−100+b)=23×c+23×1. Find the values of a, b and c. – InterviewSolution

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1.	23×(−99)=a×(−100+b)=23×c+23×1. Find the values of a, b and c.
Answer» $23 \times (- 99) = a \times (- 100 + b) = 23 \times c + 23 \times 1.$ Find the values of a, b and c.

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