1.

25.2 gm of a mixture of NaHCO_(3) and Na_(2)CO_(3) is heated strongly, 0.66 gm of CO_(2) gas is evolved then the % mass of Na_(2) CO_(3) present in original mixture is -

Answer»

0.1
0.2
0.45
0.9

Solution :`2NaHCO_(3) overset(Delta)(rarr) Na_(2)CO_(3) + H_(2)O + CO_(2)`
`n_(CO_(2)) = (0.66)/(44) = (3)/(200)`
`n_(NaHCO_(3)) = n_(CO_(2)) xx 2 = (3)/(200) xx 2 = 0.03`
`2NaHCO_(3) rarr Na_(2)CO_(3) + CO_(2) + H_(2)O`
`0.03` MOLE`N = (0.03)/(2)` mole
Mass `= 0.03 xx 84 = 2.52gm (NaHCO_(3))`
`%` by mass of `NaHCO_(3) = 10%` & `Na_(2)CO_(3) = 90%`


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