1.

25 g of MCl_(4) contains 0.5 mol chlorine then its molecular mass is:

Answer»

100g `"mol"^(-1)`
200g `"mol"^(-1)`
`150g "mol"^(-1)`
`400g "mol"^(-1)`

SOLUTION :1 mol of `MCl_(4)` contains 4 mol of CHLORINE
`because`0.5 mol chlorine is present in 25 g of `MCl_(4)`
`THEREFORE` 4 mol chlorine will be present in `(25)/(0.5)xx4` i.e. 200g of `MCl_(4)`.


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