1.

25 mL of 3.0 M HCl are mixed with 75 mL of 4.0 M HCl. If the volumes are additive, the molarity of the final mixture will be :

Answer»

4.0 M
3.75 M
4.25 M
3.5 M

Solution :If the TWO SOLUTIONS containing the same solute are mixed, the MOLARITY of the resulting solution is given as :
`M_(3)V_(3)=M_(1)V_(1)+M_(2)V_(2)`
`M_(3)=(M_(1)V_(1)+M_(2)V_(2))/V_(3)=(M_(1)V_(1)+M_(2)V_(2))/((V_(1)+V_(2)))`
`=((3.0M)XX(25mL)+(4.0M)xx(75mL))/((25+75)mL)`
=3.75 M


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