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25 " mL of " a mixture of Co, `CO_(2)` and `H_(2)` were exploded mL with 10 " mL of " oxygen. The products has a volume of 18.5 " mL of " which 17 mL absorbed by alkali. What was the composition of the original mixture? All volume measurements were made at the same temperature and pressure? |
Answer» Let `V_(1)` mL, `V_(2)mL` and `V_(3)mL` be the volumes of `CO,CO_(2)` and `H_(2)` respectively. Then `V_(1)+V_(2)+V_(3)=25` Contraction after explosion`=(25+10-18.5)mL` `=16.5mL` `(V_(1))/(2)+(3V_(3))/(2)=16.5` Absorption `-=17mL=V_(1)+V_(2)`. Solving these, we have `V_(3)=8mL`, `V_(1)=9mL and V_(2)=8mL` `thereforeCO:CO_(2):H_(2)=9:8:8` |
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