1.

25 ml of a solution of Na_(2)CO_(3) having a specific gravity of 1.25 required 32.9 ml of a solution of HCl containing 109.5 grams of the acid per litre for complete neutralization. Calculate the volume of 0.84N-H_(2)SO_(4) that will be completely neutralized by 125 grams of the Na_(2)CO_(3) solution

Answer»

460 ml
540 ml
480 ml
470 ml

Solution :`N_(1)V_(1)=N_(2)V_(2)`
`Nxx25=(109.25xx32.9)/(36.5)impliesN=(109.5xx32.9)/(36.5xx25)`
`N_(3)V_(3)=N_(4)V_(4)""(V_(3)=(m)/(d),V_(3)=(125)/(1.25))`
`(109.5xx32.9)/(36.5xx25)xx100=0.84xxV impliesV=470ml`


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