1.

25 ml of H_(2)O_(2) solution was added to the excess of acidified Kl solution . The iodine so liberated required 40 ml of 0.1 N sodium thiosulphate solution. Calculate the normality of H_(2)O_(2) solution :

Answer»

`0.08`
`0.16`
`0.02`
`0.20`

Solution :Let the NORMALITY of `H_(2)O_(2)` SOLN be`N_(x)`.
No. of milliequivalents of `Na_(2)S_(2)O_(3) ` = No. of milliequivalents of `H_(2)O_(2)`
`40 XX 0.1 = 25 xx N_(x)`
` N_(x) = (40 xx 0.1)/25 = 0.16` N


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