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26) A boy's age is one-fourth that of his father. After24 years the boy will be half the age of his father.Find their present ages.​

Answer»

Answer :

The present age of the boy is 12 years, and his FATHER age is 48 years.

Step-by-step explanation :

Let the boy's age be \sf{ \dfrac{x}{4}} years and the father's age be x years.

Given that, After 24 years, the boy will be HALF the age of his father.

THEREFORE,

Age of father, after 24 years = \sf{ \dfrac{x + 24}{2}}

And age of boy, after 24 years = \sf{ \dfrac{x}{4}} + 24

\sf{ \longrightarrow \: \dfrac{x + 24}{2} = \dfrac{x}{4} + 24}

\sf{  \longrightarrow \:  \dfrac{1}{2}x + 12 =  \dfrac{1}{4}x + 24}

\sf{  \longrightarrow \:  \dfrac{x}{2}+ 12 =  \dfrac{x}{4}+ 24}

\sf{  \longrightarrow \:  \dfrac{x}{2} - \dfrac{x}{4} = 24 - 12}

\sf{  \longrightarrow \: \dfrac{x}{4} = 12}

\sf{  \longrightarrow \: x = 12 \times 4}

\boxed{\sf{  \leadsto \: \sf{x = 48}}}  \:  \large{\red{ \star}}

Therefore, the present age of his father is 48 years.

Now, the age of boy is, We GOT x as 48, Therefore,

\sf{\longrightarrow \:  \dfrac{48}{4}}

\boxed{\sf{\leadsto \: 12}} \: \large{\purple{ \star}}

Therefore, the boy's age is 12 years.



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