1.

27.75 g of CaCl_2, dissolved in 250 ml of solutions. Find molarity of chloride ions in this solution.

Answer»

Solution :`CaCI_2 hArrCa^(2) +2CI^(-)`
formulaMassof `CaCI_2 = 111`
Molarityof `CI^(-)` IONS`=(27.75 )/( 111xx (250 )/(1000 ) )xx2`
` =( 55 .5 XX 1000)/( 111xx 250 )`
`=2`


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