27. A healthy youngman standing at a distance of 7 m froma 11 8 m high building sees a kid slipping from the topfloor. With what speed (assumed uniform) should he runto catch the kid at the arms height (1 8 m)?

27. A healthy youngman standing at a distance of 7 m froma 11 8 m high

1.	27. A healthy youngman standing at a distance of 7 m froma 11 8 m high building sees a kid slipping from the topfloor. With what speed (assumed uniform) should he runto catch the kid at the arms height (1 8 m)?
Answer» Sol. At point B (i.e. over 1.8 m from ground) the kid should be catched. For kid- initial velocity u = 0 Acceleration = 9.8 m/s2 Distance S = 11.8 – 1.8 = 10 m S = ut + ½ at2 ⇒ 10 = 0 + ½ (9.8) t2 ⇒ t2 = 2.04 ⇒ t = 1.42. In this time the man has to reach at the bottom of the building. Velocity s/t = 7/1.42 = 4.9 m/s.

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27. A healthy youngman standing at a distance of 7 m froma 11 8 m high building sees a kid slipping from the topfloor. With what speed (assumed uniform) should he runto catch the kid at the arms height (1 8 m)?

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