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27. In a gravity free space, a man of mass M standing at aheight h above the floor, throws a ball of mass m straightdown with a speed u. When the ball reaches the floorthe distance of the man above the floor will be(b) h (2-m/M)(c) 2h(d) a function of m, M, h andu |
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Answer» let speed of man be v. from principle of conservation of momentum, mu = Mv, v=mu/M, let time taken to reach ground be 't'. ut=h, t=h/u. therefore man moves vt=vh/u=mh/M, therefore, answer=h+(mh/M) =h(1+(m/M)) But the man is standing. How can he acquire velocity? Oh sorry I didn't notice it is a gravity free system. Sorry for the inconvenience. |
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