1.

27. In a gravity free space, a man of mass M standing at aheight h above the floor, throws a ball of mass m straightdown with a speed u. When the ball reaches the floorthe distance of the man above the floor will be(b) h (2-m/M)(c) 2h(d) a function of m, M, h andu

Answer»

let speed of man be v. from principle of conservation of momentum, mu = Mv, v=mu/M, let time taken to reach ground be 't'. ut=h, t=h/u. therefore man moves vt=vh/u=mh/M, therefore, answer=h+(mh/M) =h(1+(m/M))

But the man is standing. How can he acquire velocity?

Oh sorry I didn't notice it is a gravity free system. Sorry for the inconvenience.



Discussion

No Comment Found

Related InterviewSolutions