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273 K और 76 cm Hg पर एक गैस का घनत्व `1.964 g dm^(-3)` है , तो गैस है :A. `CH_(4)`B. `C_(2)H_(6)`C. `CO_(2)`D. Xe |
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Answer» Correct Answer - C हम जानते है `PV = nRT = (w)/(m)RT` या `P = (d)/(m) RT " "(because d = (w)/(V))` `d = 1.964 gdm^(-3) = 1.964 xx10^(-3) g//c.c.` `P = 76 cm Hg = 1 atm, R = 0.0821 L-atmK^(-1)mol^(-1)` `therefore m = (dRT)/(P) = (1.964 xx10^(-3) xx0.0821 xx273)/(1)=44` अतः गैस `CO_(2)` (अणुभार = 44) है । |
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