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28 g of `N_(2)` and 6 g of `H_(2)` were kept at `400^(@)C` in 1 litre vessel, the equilibrium mixture contained `27.54` g of `NH_(3)`. The approximate value of `K_(c)` for the above reaction can be `("in mole"^(-2) "litre"^(2))`A. 75B. 50C. 25D. 100 |
Answer» Correct Answer - A `{:(,N_(2)+3H_(2),hArr,2NH_(3)),("Initial conc".,1,3,0),("at equilibrium",1-0.81,3-2.43,1.62),(," "0.19,,0.57):}` No. of moles `N_(2) = (28)/(28) = 1` mole No. of moles of `H_(2) = (6)/(2) = 3` mole No. of moles of `NH_(3) = (27.54)/(17) = 1.62` moles `K_(c) = ([NH_(3)]^(2))/([N_(2)][H_(2)]^(3)) = ([1.62]^(2))/([0.19][0.57]^(3)) = 75` |
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