28. The acceleration-time graph for a particle movingY along x-axis is

1.	28. The acceleration-time graph for a particle movingY along x-axis is shown in figure. If the initial velocityof particle is -5 m/s, the velocity at t = 8 s isa (m/s)10/2461-10(1 F15 m/s(3) -15 m/s(2) +20 m/s(4) -20 m/sof 10 m pierce
Answer» The concept here is that Area under acceleration time graph gives you the change in velocity. From, 0 to 6s, Acceleration is positive. So, change in velocity = Area of upper triangle = 1/2 X Base X height= 1/2 X 6 X 10 = + 30 m/s + sign indicates that velocity is increasing. From 6 to 8s, acceleration is negative. So, change in velocity= Area of lower triangle= 1/2 X Base X height= 1/2 X 2 X -10 = -10 m/s - sign indicates that velocity is decreasing. Total Area under Graph= Upper Triangle Area + Lower Triangle Area.= 30 - 10= 20 m/s So, final velocity= Initial velocity + Total Area under Graph= -5 + 20= 15 m/s (Ans)

28. The acceleration-time graph for a particle movingY along x-axis is shown in figure. If the initial velocityof particle is -5 m/s, the velocity at t = 8 s isa (m/s)10/2461-10(1 F15 m/s(3) -15 m/s(2) +20 m/s(4) -20 m/sof 10 m pierce

Answer»

The concept here is that Area under acceleration time graph gives you the change in velocity.

From, 0 to 6s, Acceleration is positive. So, change in velocity = Area of upper triangle = 1/2 X Base X height= 1/2 X 6 X 10 = + 30 m/s

+ sign indicates that velocity is increasing.

From 6 to 8s, acceleration is negative. So, change in velocity= Area of lower triangle= 1/2 X Base X height= 1/2 X 2 X -10 = -10 m/s

- sign indicates that velocity is decreasing.

Total Area under Graph= Upper Triangle Area + Lower Triangle Area.= 30 - 10= 20 m/s

So, final velocity= Initial velocity + Total Area under Graph= -5 + 20= 15 m/s (Ans)

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