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`29` electron are remove from `Zn` atom `(Z=30)` by certain means . The minimum energy needed to remove the `30th` electron , will be :A. `12.24keV`B. `408keV`C. `0.45keV`D. `765keV` |
Answer» Correct Answer - A After removing 29 electrons, Zn atom will become `Zn^(+29) therefore E=13.6Z^(2)eV=12,24KeV` |
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