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2A planet of mass m moves arounM in an elliptical orbit. The maximumdistances of the planet from the sunthe sun of masse maximum and minimum2.respectively. The time period oproportional to(2) r 3/2(4) (r1- r2)372(1) r,373/2(3) (r, + 2)3/2t the centre of sun is |
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Answer» Given the perihelion = r2 = shortest distance of a planet from Sun aphelion = r1 = longest distance of planet from Sun mass of planet = m. mass of Sun = M So the length of the major axis of the Elliptical orbit of the planet = r1 + r2. Semimajor axis = R = (r1 + r2)/2. According to Kepler's laws: The square of time period T of a planet revolving around Sun is proportional to the cube of semi major axis R of the elliptical orbit of the planet. T² ∞ R³ T∞R³/² T ∞ [r1 + r2] ³/² Answer. option 3 |
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