1.

2Ag^(+) + C_(6)H_(12) O_(6) + H_(2)O rightarrow 2Ag(s) + C6H_(12)O_(7) + 2H^(+) Find ln K of this reaction.

Answer»

`66.13`
`58.38`
`28.30`
`46.29`

Solution :`E_(CELL)^(@)=(RT)/(NF)lnK`
`0.8-0.05=(0.0591)/(2xx2.303) lnK`
`THEREFORE lnK=((0.8-0.05)xx2xx2xx2.303)/(0.0591)=58.45`


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