`2CaSO_(4)(s)hArr22CaO(s)+2SO_(2)(g)+O_(2)(g), DeltaHgt0` Above equilibrium is established by taking some amout of `CaSO_(4)(s)` in a closed container at `1600K` Then which of the following may be correct option.A. Moles of `CaO(s)` will increase with the increase in temperatureB. If the voulme of the container is doubled at equilibrium then partial pressure of `SO_(2)(g)` will change at new equilibriumC. If the volume of the container is halved partial pressure of `O_(2)(g)` at new equilibrium will remain sameD. If two moles of the He gas is added at constant pressure then the moles of `CaO(s)` will increase.

`2CaSO_(4)(s)hArr22CaO(s)+2SO_(2)(g)+O_(2)(g), DeltaHgt0` Above equili

1.	`2CaSO_(4)(s)hArr22CaO(s)+2SO_(2)(g)+O_(2)(g), DeltaHgt0` Above equilibrium is established by taking some amout of `CaSO_(4)(s)` in a closed container at `1600K` Then which of the following may be correct option.A. Moles of `CaO(s)` will increase with the increase in temperatureB. If the voulme of the container is doubled at equilibrium then partial pressure of `SO_(2)(g)` will change at new equilibriumC. If the volume of the container is halved partial pressure of `O_(2)(g)` at new equilibrium will remain sameD. If two moles of the He gas is added at constant pressure then the moles of `CaO(s)` will increase.
Answer» Correct Answer - A::C::D (A) As reaction is endothermic therefore it will go in the forward direction hence moles of `CaO` will increase. (B) With the increase or decrease of volume partial pressure of the gases will remain same. (C) Due to the addition of inert gas at constant pressure reaction will proceed in the direction in which more number of gaseous moles are formed.

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