1.

2F of electricity is passed through 20 L of a solution of aquous solution of KCI. Calculate the pH of the solution.

Answer»


Solution :`KCl overset("Electrolysis") to underset("at anode")(Cl_(2)(G)) + underset("at CATHODE")(H_(2)(g)) + underset("in solution")(OH^(-))`
IF = 1eq of `H_(2)(g)` = 1 eq of `Cl_(2) -=` 1 eq of `OH^(-)` IONS 2F = 2 eq of `OH^(-)`
`[OH^(-)] = (2eq)/("Volume in L") = 2/(20 L) = 10^(-1) N` or M
`therefore pOH =- log(10^(-1)) =1`
`pH = 14-1 = 13`


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