1.

2g of a gas X are introduced into an evacuated flask kept at 25^(@)C. The pressure is found to be 1 atm. If 3g of another gas Y are added to the same flask, the total pressure becomes 1.5 atm. Assuming that ideal behaviour, the molecular mass ratio of M_(x) and M_(y) is

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Solution :DALTON's law `P= P'_(X)+P'_(Y)`
`1.5 = 1.0 + P'_(Y) `or `P'_(Y)=0.5 ATM`
for gas `X, P'_(X) XX V = (2)/(M_(X))RT`
for gas `Y, P'_(Y) xxV = (3)/(M_(Y))RT`
`implies (P'_(X))/(P'_(Y))=(2)/(3)(M_(Y))/(M_(X))` or `(M_(Y))/(M_(X))= (3)/(2) xx (P'_(X))/(P'_(Y))=(3xx1.0)/(2xx0.5)=3`


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