1.

2HgtoHg_(2)^(++),E^(@)=+0.855V HgtoHg^(2+),E^(@)=0.799V Equilibrium constant for the reaction Hg+Hg^(2+)toHg_(2)^(++) at 27^(@)C is

Answer»

89
82.3
79
none of these

Solution :`E^(@)` for the given reaction
`=0.855-0.799=0.056V`
`E_(cell)^(@)=(0.0591)/(2)"LOG"K_(c)`
or `logK_(c)=(0.056xx2)/(0.059)=1.8983`
`K_(c)`=ANTILOG `1.8983=79:12=79`


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