2M solution of Na_(2)CO_(3) is boiled in a closed container with excess of CaF_(2) .Very little amount of CaCO_(3) and NaF are formed.If the solubility product (K_(sp)) of CaCO_(3) is x and molar solubility of CaF_(1) is y.Find the molar concentration of F^(-) in resulting solution after equilibrium is attained.

2M solution of Na_(2)CO_(3) is boiled in a closed container with exces

1.	2M solution of Na_(2)CO_(3) is boiled in a closed container with excess of CaF_(2) .Very little amount of CaCO_(3) and NaF are formed.If the solubility product (K_(sp)) of CaCO_(3) is x and molar solubility of CaF_(1) is y.Find the molar concentration of F^(-) in resulting solution after equilibrium is attained.
Answer» SOLUTION :`{:(,Na_(2)CO_(3)+,CaF_(2)(s)hArr,2NaF(AQ)+,CaCO_(3)(s)),(t=0,2,-,0,-),(t=eq,2-a,-,2a,-):}` where is very small For `CaCO_(3),K_(sp)=x=[Ca^(2+)][CO_(3)^(2-)]=[Ca^(2+)]xx2( :.CO_(3)^(2-)` mainly COMING from `Na_(2)CO_(3)` `[Ca^(2+)]=(x)/(2)` For `CaF_(2),K_(sp)=4y^(3)=((x)/(2))[F^(-)]^(2)RARR [F^(-)]=sqrt((8y^(3))/(x))`