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2N_(2)O_(5)rarr NO_(2)+O_(2), (d[N_(2)O_(5)])/(dt)=k_(1)[N_(2)O_(5)], (d[NO_(2)])/(dt)=k_(2)[N_(2)O_(5)] and (dO_(2))/(dt)=k_(3)[N_(2)O_(5)], the relation between k_(1), k_(2) and k_(3) is |
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Answer» `2k_(1)=4k_(2)=k_(3)` |
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