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`2NO_(2)(g)to N_(2)O_(4)(g)` `DeltaU_(f)^(@)[N_(2)O_(4)(g)]=2kcal//"moleand "DeltaU_(reaction)^(@)=-16kcal//mol,` then calculate `DeltaH_("formation" )^(@)=-16kcal//mol,` then calculate `DeltaH_("formation")^(@) of NO_(2)at 727^(@)C:`A. 9kcal/molB. 4.5kcal/molC. 8kcal/molD. 10kcal/mol |
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Answer» Correct Answer - c |
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