1.

2NO_(2)hArr 2NO+O_(2),K=1.6xx10^(-12)NO+1/2O_(2)hArrNO_(2),K'=?

Answer»

`K'(1)/(K^(2))`
`K'=1/K`
`K'=(1)/(sqrtK)`
NONE of these

Solution :`2NO_(2)hArr2NO+O_(2)""...(i)`
`K=1.6xx10^(-12)`
`NO+1/2O_(2)hArrNO_(2)""...(ii)`
REACTION (ii) is half of reaction (i)
`K=([NO]^(2)[O_(2)])/([NO_(2)]^(2))""...(i)`
`K=([NO_(2)])/([No][O_(2)]^(1//2))""...(ii)`
On multiplying (i) and (ii)
`KxxK'=([NO]^(2)[O_(2)])/([NO_(2)]^(2))xx([NO_(2)])/([NO][O_(2)]^(1//2))`
`=([NO][O_(2)]^(1//2))/([NO_(2)])=1/K`
`KxxK'=1/K,K=(1)/(K^(2)),K'=(1)/(sqrt(K)).`


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