1.

2sin²theta - 3cos²theta 1/2tan²theta​

Answer»

sinθ=cosθcosθsinθ=cosθcosθtanθ=1=tan45oθ=45oTherefore, 2tanθ+sin2θ−1=2tan45o+sin245o−1=2×(1)2+(21)2−1=2+21−1=23.



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