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2SO_2+O_2 hArr 2SO_3 Starting with 2 mol of SO_2 and 1 mol of O_2 in 1-L flask, mixture required 0.4 mol of MnO_4^- in acidic medium . Find the K_c value

Answer»

SOLUTION :`5 SO_2+2MnO_4 to 2Mn^(2+)+5SO_4^2`
2 MOL of `MnO_4^(-)-= 1 mol SO_2`
`therefore 0.4 ml "of" Mno_4^(-)-=1 mol SO_2`
`{:(2SO_2,+,O_2,hArr,2SO_3),(2,"",1,"",0),((2-2x),"",(1-x),"",2x):}`
(2-2x)=1 mol (as DETERMINED by `MnO_4^-`)
`therefore [SO_3]=(2x)/V=1M, [SO_2^-]=(2-2x)/V=1M`
`[O_2^-]=((1-x))/(V=0.5 M,K_c=([SO_3]^2)/([SO_2]^2[O_2])=2`


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