`2tanx-cotx+1=0` – InterviewSolution

InterviewSolution

1.	`2tanx-cotx+1=0`
Answer» Correct Answer - `x=npi+(3pi)/(4)orx=mpi+(-1)^(n)(pi)/(2),"where m "ninI` The given equations is `2tan^(2)x+tanx-1=0` `rArr(tanx+1)(2tanx-1)=0` `rArrtanx=-1ortanx=(1)/(2)` `rArrtanx="tan"(3pi)/(4)ortanx=tan("tan"^(-1)(1)/(2))` `rArrx=npi+(3pi)/(4)orx=mpi+"tan"^(-1)(1)/(2), "where m "n in I`.

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