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2x+3(3x-7)=19 equation |
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Answer» 1Distribute2+3(3−7)=192x+{\COLOR{#c92786}{3(3x-7)}}=192x+3(3x−7)=192+9−21=192x+{\color{#c92786}{9X-21}}=192x+9x−21=192Combine LIKE terms2+9−21=19{\color{#c92786}{2x}}+{\color{#c92786}{9x}}-21=192x+9x−21=1911−21=19{\color{#c92786}{11x}}-21=1911x−21=193Add 212121 to both sides of the equation11−21=1911x-21=1911x−21=1911−21+21=19+2111x-21+{\color{#c92786}{21}}=19+{\color{#c92786}{21}}11x−21+21=19+214SimplifyAdd the numbersAdd the numbers11=4011x=4011x=405Divide both sides of the equation by the same term11=4011x=4011x=401111=4011\frac{11x}{{\color{#c92786}{11}}}=\frac{40}{{\color{#c92786}{11}}}1111x=11406SimplifyCancel terms that are in both the NUMERATOR and denominator=4011x=\frac{40}{11}x=1140Show lessSolution=4011Mark me brainlist |
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