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2x/5 - 3(2x-5)/3Part (d)

Answer»

\huge \mathtt \red{answer}

\bf \red{ \frac{2x}{5}  -  \frac{<klux>3</klux>(2x - 5)}{3} }

TAKE L.C.M. of 3 and 5=15

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\large{=> \frac{2x}{5}  \times  \frac{3}{3}  =  \frac{6x}{15} }

\large{=> \frac{3(2x - 5)}{3}  \times  \frac{5}{5} =  \frac{15(10x - 25)}{15}}

\large{ =>\frac{6x - 15(10x - 25)}{15} }

\large{=>\frac{6x - 10x - 15 + 25}{15} }

{=> - 4x + 10}

\bf \red{❥Hope  \: it  \: helps \:  you....}



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