2x+b/y-a =2a ...pls aswer

1.	2x+b/y-a =2a ...pls aswer
Answer» ANSWER: The given system of equations are: (a - b)x + (a + b)y = 2a2 - 2B2 So, (a - b)x + (a + b)y - 2a2 - 2b2 = 0 (a - b)x + (a + b)y - 2(a2 - b2) = 0 ........(i) And (a + b)(x + y) = 4AB So, (a +b)x + (a + b)y - 4ab = 0 ..........(II) The given system of equation is in the FORM of a1x + b1y - c1 = 0 and a2x + b2y - c2 = 0 Compare (i) and (ii) , we get a1 = a - b, b1 = a + b, c1 = -2(a2 + b2) a2 = a + b, b2 = a + b, c2 = -4ab By cross-multiplication method x2(a+b)(a2−b2+2ab) =−y2(a−b)(a2+b2) =1−2b(a+b) Now, x2(a+b)(a2−b2+2ab)=1−2b(a+b) ⇒x=2ab−a2+b2b And, −y2(a−b)(a2+b2)=1−2b(a+b) ⇒y=(a−b)(a2−b2)b(a+b) The solution of the system of equations are 2ab−a2+b2b and (a−b)(a2−b2)b(a+b) respectively. Step-by-step explanation:

Answer»

The given system of equations are:

(a - b)x + (a + b)y = 2a2 - 2B2

So, (a - b)x + (a + b)y - 2a2 - 2b2 = 0

(a - b)x + (a + b)y - 2(a2 - b2) = 0 ........(i)

And (a + b)(x + y) = 4AB

So, (a +b)x + (a + b)y - 4ab = 0 ..........(II)

The given system of equation is in the FORM of

a1x + b1y - c1 = 0

and a2x + b2y - c2 = 0

Compare (i) and (ii) , we get

a1 = a - b, b1 = a + b, c1 = -2(a2 + b2)

a2 = a + b, b2 = a + b, c2 = -4ab

By cross-multiplication method

x2(a+b)(a2−b2+2ab) =−y2(a−b)(a2+b2) =1−2b(a+b)

Now, x2(a+b)(a2−b2+2ab)=1−2b(a+b)

⇒x=2ab−a2+b2b

And, −y2(a−b)(a2+b2)=1−2b(a+b)

⇒y=(a−b)(a2−b2)b(a+b)

The solution of the system of equations are 2ab−a2+b2b and (a−b)(a2−b2)b(a+b) respectively.

Step-by-step explanation:

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