3x−4y+7z=0.....(i)2x−y−2z=0......(ii)3x 3 −y 3 −z 3 =8....(iii)Applying CROSS MULTIPLICATION on (i) and (ii)8+7x = −6−14−y = −3+8z 15x = 20y = 5z 3x = 4y =z=K⇒x=3K,y=4k,z=kSubstituting x,y and z in (iii)⇒x=3k,y=4k,z=k3(3k) 3 −(4k) 3 +(k) 3 =8k 3 =1k=1⇒x=3,y=4,z=1
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