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3(1/3)^3 - 10(1/3)^2 - 27(1/3) +10. Please solve this with proper explanation i will give thanks and the answer should be 0. |
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Answer» Step-by-step explanation: hlo mate here's your answerConsider the triangles △ABC and △PQR ADandPMbeing the mediums from VERTEX AandPrespectively. Given : △ABC∼ △PQR To prove : P Q A B = PM AD It is given that △ABC∼ △PQR ⇒ P Q A B = Q R B C = P R A C [ from the side-ratio property of SIMILAR △ s] ⇒ ∠A= ∠P,∠B= ∠Q,∠C= ∠R BC= 2BD;QR= 2 QM [P,M being the mid points of BC q QR respectively] ⇒ P Q A B = 2 Q M 2 B D = P R A C ⇒ P Q A B = Q M B D = P R A C Now in △ABDq△PQM P Q A B = Q M B P..[ from (1)] ∠B= ..[ from (A)] ⇒ △ABD∼ △PQM SAS property of similar △s] from the side property of similar△s HENCE proved P Q A B = PM AD i hope its help you mark as brainlist |
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