1.

(3-2√5)/(3+2√5) = a√5-19/11b find the value of a and b​

Answer»

ANSWER:

a=-12/11

b=-19/29

Step-by-step EXPLANATION:

RATIONALISING the DENOMINATOR

(3-2√5)/(3+2√5)×(3-2√5)/(3-2√5)=a√5-19/11b

(3-2√5)^2/9-20=a√5-19/11b

9+20-12√5/11=a√5-19/11b

29-12√5/11=a√5-19/11b

29/11-12√5/11=a√5-19/11b

-12√5/11+29/11=a√5-19/11b

On COMPARING,

-12√5/11=a√5

a=-12/11

29/11=-19/11b

b=-19/29



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