1.

3.2 g of oxygen and 0.2 g of hydrogen are placed in a 1.12 L flask at 0^(@)C. The total pressure of the gas mixture will be

Answer»

<P>1 ATM
4 atm
3 atm
2 atm

Solution :Moles of `O_(2) = ( 3.2 )/( 32) = 0.1`,
Moles of `H_(2) = ( 0.2) /( 2) = 0.1`
PRESSURE, `p = ( n RT )/( V )`
`= ( 0.2 xx 0.082 xx 273 )/( 1.12) = 4 atm`


Discussion

No Comment Found