1.

(3.50 xx 10^2 mL) – (0.0225 L)may be written to correct significant digits :

Answer»

`3.28 XX 10^2 ML`
`0.3275 L`
`0.33L`

SOLUTION :`{:(3.50 xx 10^2 mL),(-0.225 xx 10^2 mL),(overline(3.275 xx 10^2 mL )):}`
` = 3.28 xx 10^2 mL`
(UPTO two decimal PLACES as in 0.50 )


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