1.

3.6gr of O_2 is adsorbed on 1.2gr of metal powder what volume of O_2 adsorbed per gram of the adsorbent at latm and 273K

Answer»

2.1 
0.19 
1
None 

SOLUTION :Mass of `O_2` per gram of ADSORBENT = `(3.6)/(1.2) = 3`
No. of MOLES of `O_2` pergram of adsorbent = `3/32`
Volume of `O_2` per gram of adsorbent `3/32 XX (0.0821 xx 273)/1 = 2.1`


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