1.

3.92g//Lofa sampleofferrousammoniumsulphatereactscompletelywith50 mL(N )/(10 )KMnO_4solutionthe percentagepurityof the sampleis

Answer»

50
`78.4`
`80.0`
`39.2`

SOLUTION :`N_1xxV_1= N_2 xxV_2`
` [FeSO_4(NH_4)_2 SO_4 .^H_2O] [KMnO_4]`
` N_1xx 100 =1/100=1/10xx 50orN_1 =(1)/( 200)`
eq WT of ` FeSO_4.(NH_4)_2 SO_4 .^H_2O= Molwt= 392`
` THEREFORE ` Strengthofpuresalt`= 392 xx (1)/(200 ) = 1.96gL^(-1)`
` therefore` % purity = `( 1.96)/ ( 3.92 ) xx 100 =50 % `


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