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3. A field in the form of a parallelogram has base 200 m and altitude 80 m long. Find the cost of watering the field at Rupees 1per 100m². |
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Answer» Answer: 160 RUPEES Step-by-step explanation: altitude =80 m area of parallelogram =b×h = 200×80 =16000 m² cost of watering PER 100 m² = 1 rupee cost of watering per m² = 1/100 rupee cost of watering 16000 m² = 16000×1/100 = 160 rupees |
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