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3) A number couisto of two digits whate sum is 8. it & is added to the number its alligits allgits are reversed. the number

Answer»

Let ONE digit of the number be X , then its ten DIGITS digits will be (8−x) . So , given number =10(8−x)+x =80−10x+x =80−9xNow if digits are reversed , then Number OBTAINED =10x+(8−x) =10x+8−x =9x+8According to question (80−9x)+18=9x+8 98−9x=9x+8 90=18x x=5⇒ given number =80−9x =80−9×5 =80−45 =35



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