1.

3.A planet of mass mmoves around the sun of massin an elliptical orbit. The maximum and minimumdistances of the planet from the sun are r, and r2respectively. The time period of the planet isproportional to(2) r23/2(4) (r,-12)32(3) (, 2)321 2

Answer»

Given the perihelion = r2 = shortest distance of a planet from Sun aphelion = r1 = longest distance of planet from Sun mass of planet = m. mass of Sun = M

So the length of the major axis of the Elliptical orbit of the planet = r1 + r2.

Semimajor axis = R = (r1 + r2)/2.

According to Kepler's laws:

The square of time period T of a planet revolving around Sun is proportional to the cube of semi major axis R of the elliptical orbit of the planet.

T² ∞ R³ T∞R³/² T ∞ [r1 + r2] ³/² Answer.

Actual value of the time period is given by:



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