3. Abus travels at a speed of 48) 13LKIAnkit drives his scooter at 54 km/h. He takes 3 hours 20 minutes to reach his destinationHow far is his destination?manis running at a speed of 12 km/h. How much distance will he cover in 12 minutes?

3. Abus travels at a speed of 48) 13LKIAnkit drives his scooter at 5

1.	3. Abus travels at a speed of 48) 13LKIAnkit drives his scooter at 54 km/h. He takes 3 hours 20 minutes to reach his destinationHow far is his destination?manis running at a speed of 12 km/h. How much distance will he cover in 12 minutes?
Answer» I1 = Current flowing through the outer circuitI2 = Current flowing through branch ABI3 = Current flowing through branch ADI2 - I4 = Current flowing through branch BCI3 + I4 = Current flowing through branch CDI4 = Current flowing through branch BDFor the closed circuit ABDA, potential is zero i.e.,10I2 + 5I4 - 5I3 = 02I2 + I4 - I3 = 0I3 = 2I2 + I4 … (1)For the closed circuit BCDB, potential is zero i.e.,5(I2 - I4) - 10(I3 +I4) - 5I4 = 05I2 + 5I4 - 10I3 - 10I4 - 5I4 = 05I2 - 10I3 - 20I4 = 0I2 = 2I3 + 4I4 … (2)For the closed circuit ABCFEA, potential is zero i.e.,- 10 + 10 (I1) + 10(I2) + 5(I2 - I4) = 010 = 15I2 + 10I1 - 5I43I2 + 2I1 - I4 = 2 … (3)From equations (1) and (2), we obtainI3 = 2(2I3 + 4I4) + I4I3 = 4I3 + 8I4 + I4- 3I3 = 9I4- 3I4 = + I3 … (4)Putting EQUATION (4) in equation (1), we obtainI3 = 2I2 + I4- 4I4 = 2I2I2 = - 2I4 … (5)It is evident from the given figure that,I1 = I3 + I2 … (6)Putting equation (6) in equation (1), we obtain3I2 +2(I3 + I2) - I4 = 25I2 + 2I3 - I4 = 2 … (7)Putting equations (4) and (5) in equation (7), we obtain5( - 2 I4) + 2( - 3 I4) - I4 = 2- 10I4 - 6I4 - I4 = 217I4 = - 2.Equation (4) reduces toI3 = - 3(I4)Total current = 10/17 A