3. Calculate number of moles present in following:(a)10.0g of calcium

1.	3. Calculate number of moles present in following:(a)10.0g of calcium carbonate
Answer» Formula:No of moles=weight of calcium carbonate/molecular weight =10/(40+12+ (16×3))since Ca=50; C=12; O=16=10/100=0.1 moles no of moles= mass in gram/ gram molecular massmass in gram= 10ggram molecular mass of caco3 = 40+12+3*16= 100so no of moles= 10/100= 0.1 moles. 1mole of caco3 = GMM of caco3 1mole of caco3 =100g 100g of caco3 =1mole of caco3 10g of caco3 = 1×10÷100 =0.1mole

3. Calculate number of moles present in following:(a)10.0g of calcium carbonate

Answer»

Formula:No of moles=weight of calcium carbonate/molecular weight

=10/(40+12+ (16×3))since Ca=50; C=12; O=16=10/100=0.1 moles

no of moles= mass in gram/ gram molecular massmass in gram= 10ggram molecular mass of caco3 = 40+12+3*16= 100so no of moles= 10/100= 0.1 moles.

1mole of caco3 = GMM of caco3 1mole of caco3 =100g 100g of caco3 =1mole of caco3 10g of caco3 = 1×10÷100 =0.1mole